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  • 1 answers

Sonali Yadav 8 hours ago

2
  • 1 answers

Swaraj Rout 18 hours ago

3x² - 12x By taking 3x as common 3x(x - 4)
  • 2 answers

Swaraj Rout 18 hours ago

By using the algebraic identity of ( a + b )³ = a³ + b³ + 3a²b + 3ab² => (2a)³ + (b)³ + 3(2a)²(b) + 3(a)(b)² => (2a + b)³

7 A Arnav Sharma 1 day, 22 hours ago

jzj
  • 2 answers

Swaraj Rout 18 hours ago

X - 1 = 0 X = 1 P(1) = 1² - 2 - 3 P(1) = 1 - 2 - 3 P(1) = -1 -3 P(1) = -4 Answer is -4

Ramesh Rajput Rohuaa 3 days, 22 hours ago

This answer is 0
  • 1 answers

Akanksha Goyal 3 days, 19 hours ago

8.4852
  • 1 answers

Akanksha Goyal 3 days, 19 hours ago

8.4852
  • 1 answers

Swaraj Rout 18 hours ago

2y² - y - 1 2y² - 2y - y - 1 2y(y - 1) + 1(y - 1) (2y + 1)(y - 1)
  • 2 answers

Ramesh Rajput Rohuaa 3 days, 22 hours ago

375/1000

Satpal Dev 4 days, 12 hours ago

375 upon 1000
  • 0 answers
  • 5 answers

Swaraj Rout 18 hours ago

It can be but you have to put minus outside the bracket and square 8 only like this -(8)²

Akanksha Goyal 3 days, 19 hours ago

Not correct because square and Square root can't be in negative

Chandan Singla 4 days, 7 hours ago

-8

Vp Vp 4 days, 17 hours ago

-8

A&A Singh 5 days, 9 hours ago

_8
  • 1 answers

Anvi Agrawal 5 days, 8 hours ago

3(x+5)2 - 2(x+5) - 8
  • 1 answers

Bhavishya Gupta Gupta 1 day, 17 hours ago

Jm
  • 0 answers
  • 2 answers

Diya Ziya 3 days, 9 hours ago

reason is an integer can be negative and positive but whole numbers are only positive

Diya Ziya 3 days, 9 hours ago

answer is false
  • 4 answers

A&A Singh 5 days, 9 hours ago

No because zero is not integers

Naitik Singh 1 week, 1 day ago

Yes zero is a rational no we can write it as 0/1.

Saad Saad 1 week, 1 day ago

234 ie

Nikhil Kumar 1 week ago

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  • 0 answers
  • 1 answers

Ritika Dua. 1 week, 3 days ago

675/1000
  • 3 answers

Shaurya Pratap Singh 5 days, 8 hours ago

Udjhsokd

Ritika Dua. 1 week, 3 days ago

9x²+6xy+y² Using identity (a+b)²=a²+2ab+b² (3x)²+2(3x)(y)+(y)² *(3x+y)²* answer

Dhruv Padhan 1 week ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
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  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
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Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.
  • 1 answers

Ritika Dua. 1 week, 3 days ago

This question is not correct
  • 0 answers
  • 2 answers

Punit Chaudhary 1 week, 4 days ago

(99)³

Usha Subhash 1 week, 5 days ago

Draw 4cm in line from a point (O)and 1cm perpendicular to the end of the line . Join the point(O) to top of 1cm line (P). Form (O) to (P) mark on rounder it forms √17 √(4²+1²) = √(16+1)=√17
  • 3 answers

Sushma Diwan 1 week, 4 days ago

2²+3x-4 4-4+3x We will cancel 4-4 positive and negative Then, remain is 3x

Usha Subhash 1 week, 5 days ago

If you are talking about 2x²+3x-4 The roots are approx 0.85 and -2.35

Usha Subhash 1 week, 5 days ago

The question is not perfect
  • 4 answers

Navya Navya Singh 1 week, 6 days ago

Case study based questions chapter 2 polynomials

Putta Thrishitha 1 week, 6 days ago

3.1748

Lakiraj Solunke 1 week, 6 days ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
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Lakiraj Solunke 1 week, 6 days ago

Interger multiple rational

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