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Jiyab Kumar 8 hours ago

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Guneet Kaur 10 hours ago

To determine the mass of carbon tetrachloride (CCl4) produced and the mass of excess reagent, we need to first balance the chemical equation for the reaction between carbon and chlorine: C + 2Cl2 -> CCl4 From the balanced equation, we can see that 1 mole of carbon reacts with 2 moles of chlorine to produce 1 mole of carbon tetrachloride. Next, we need to calculate the moles of carbon and chlorine provided: Moles of carbon (C): Moles of C = Mass of C Molar mass of C = 10   g 12.01   g/mol Moles of C= Molar mass of C Mass of C ​ = 12.01g/mol 10g ​ Moles of chlorine (Cl2): Moles of Cl 2 = Mass of Cl 2 Molar mass of Cl 2 = 100   g 2 × 35.45   g/mol Moles of Cl 2 ​ = Molar mass of Cl 2 ​ Mass of Cl 2 ​ ​ = 2×35.45g/mol 100g ​ From the stoichiometry of the reaction, we know that 1 mole of carbon reacts with 2 moles of chlorine to produce 1 mole of carbon tetrachloride. Moles of CCl4 produced: Since the reaction is stoichiometric, the moles of CCl4 produced will be equal to the moles of carbon (C). Now, let's calculate: Moles of C: Moles of C = 10   g 12.01   g/mol ≈ 0.832   mol Moles of C= 12.01g/mol 10g ​ ≈0.832mol Moles of Cl2: Moles of Cl 2 = 100   g 2 × 35.45   g/mol ≈ 1.41   mol Moles of Cl 2 ​ = 2×35.45g/mol 100g ​ ≈1.41mol Since 1 mole of carbon reacts with 2 moles of chlorine, we have excess chlorine: Moles of excess Cl2: Excess moles of Cl 2 = ( Moles of Cl 2 ) − 2 × ( Moles of C ) Excess moles of Cl 2 ​ =(Moles of Cl 2 ​ )−2×(Moles of C) Now, let's calculate: Excess moles of Cl 2 = 1.41   mol − 2 × 0.832   mol = 1.41   mol − 1.664   mol = − 0.254   mol Excess moles of Cl 2 ​ =1.41mol−2×0.832mol=1.41mol−1.664mol=−0.254mol Since the result is negative, it indicates that chlorine is in excess. However, since reactants cannot have negative moles, we take the absolute value of the result to find the moles of excess chlorine. So, the absolute value of 0.254   mol 0.254mol of chlorine is in excess. To find the mass of excess chlorine: Mass of excess Cl2: Mass of excess Cl 2 = Excess moles of Cl 2 × Molar mass of Cl 2 Mass of excess Cl 2 ​ =Excess moles of Cl 2 ​ ×Molar mass of Cl 2 ​ Now, let's calculate: Mass of excess Cl 2 = 0.254   mol × 2 × 35.45   g/mol ≈ 17.98   g Mass of excess Cl 2 ​ =0.254mol×2×35.45g/mol≈17.98g So, approximately 17.98   g 17.98g of chlorine is in excess. Finally, to find the mass of carbon tetrachloride produced: Mass of CCl4 produced: Since 1 mole of carbon reacts with 1 mole of carbon tetrachloride, the mass of CCl4 produced will be equal to the mass of carbon. So, the mass of carbon tetrachloride produced is approximately 10g
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  • 2 answers

Abhishek M Ganiger Abhi 2 days, 10 hours ago

Hi sir

Gagan Deep 2 weeks, 5 days ago

1/2 mole of carbon is burnt
  • 2 answers

Aszad Imam 2 weeks, 2 days ago

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Aszad Imam 2 weeks, 2 days ago

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  • 4 answers

Lakshna Sree 1 month ago

0.69m/s

Apurva Sharma 1 month ago

41.6

Arsh Tiwari 1 month, 1 week ago

41.6 m/s

Its Myself 1 month, 2 weeks ago

38.41m/s
  • 2 answers

Its Myself 1 month, 2 weeks ago

Metal usually donates electron to become stable whereas non metal usually receives electron to become stable.
Metals are acidic in nature which means they contain acidic oxides and non metals are basic in nature which means they contain basic oxides
  • 1 answers

Priyanshu Kumar 2 months, 1 week ago

F- exhibits only negative oxidation state . Cs- exhibits only positive oxidation state I- exhibits only negative and positive oxidation state Ne- exhibits neither the negative nor does the positive oxidation state
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Pratham Vaishnav 2 months, 3 weeks ago

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Aditya Jain 2 months, 2 weeks ago

Endothermic rxn. = the reaction accompanied by absorption of heat is called Endothermic rxn . E.g. 2NH3 ----- N2 + 3H2

Aditya Jain 2 months, 2 weeks ago

Exothermic = the reaction accompanied by release of energy in the form of heat or light is called exothermic reaction E.g. c+o2 --- co2
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Himanshu Garg 2 months ago

CH3CH2OH + 2 HCL =CH3C(Cl)(Cl) + Alcoholic KOH = CHCH
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Himanshu Garg 2 months ago

+6

Shivam Gupta 3 months ago

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Ankur Tiwary 2 months ago

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